Contoh Soal Reaksi Perletakan Balok

Adi Hamdani    April 19, 2013    analisa struktur    Comment   

∑H = 0
HA-2 cos 60° = 0
HA = 2 cos 60°
= 2 . ½
= 1 t

∑MA = 0
4(3)-vb(6)+2sin 60° (9) = 0
12 - 6vb + 15.588 = 0
6vb = 15.588  + 12
Vb = 4.598 t

∑MB = 0
Va(6)-4(3)+2 sin 60°(30) = 0
Va = 4(3)-2 sin 60(3)6
Va = 1.134 t

Cek  ∑V = 0
Va + vb – 4 – 2 sin 60° = 0
1.134 + 4.598 – 2 sin 60° = 0
0 = 0  ok !!!